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Why Students Make Errors in the Solutions Chapter of Chemistry

By QuizPerCard · Leaving Cert Chemistry · 18 April 2026

Concentration in moles per litre, in grams per litre, and in percentage are three different numbers. Solutions calculations for Leaving Cert Chemistry.

Students can define molarity and molality but cannot connect them to each other or to actual experimental contexts. They treat every concentration unit as an isolated formula rather than as a different way to describe the same physical reality.

The Core Problem: Too Many Concentration Units, No Unified Picture

The Solutions chapter introduces molarity, molality, mole fraction, mass percentage, parts per million, and normality.

Students try to memorise each formula separately. This creates a jumbled mess where they confuse which unit uses volume of solution versus mass of solvent, or which is temperature-dependent versus temperature-independent.

Molarity uses the volume of solution. Molality uses the mass of solvent. This single distinction separates the two most commonly confused units.

Mistake 1: Forgetting That Molarity Changes With Temperature

Students use molarity and molality interchangeably in calculations involving temperature changes.

Molarity is temperature-dependent because it uses volume, and volume expands with heat. Molality does not change with temperature because it is based on mass, which is temperature-independent.

If a question asks about concentration at a different temperature and you use molarity as if it were constant, your answer will be wrong. Use molality for temperature-varying scenarios.

Why Raoult's Law Feels Counterintuitive

Students learn Raoult's law but cannot intuitively explain why adding a non-volatile solute lowers vapour pressure.

Vapour pressure depends on how easily solvent molecules escape from the liquid surface. When you dissolve a solute, solute particles occupy some of the surface. Fewer solvent molecules are at the surface, so fewer escape, and vapour pressure drops.

The mole fraction of solvent tells you what fraction of surface positions are occupied by solvent. A lower mole fraction of solvent means lower vapour pressure. This is Raoult's law, not a formula to memorise but a physical picture to visualise.

Mistake 2: Confusing Positive and Negative Deviations From Raoult's Law

Students know that solutions can show positive or negative deviations but cannot predict which type a given solution will show.

Positive deviation occurs when solute-solvent interactions are weaker than pure component interactions. Molecules escape more easily, raising vapour pressure above the ideal value. Example: ethanol and water.

Negative deviation occurs when solute-solvent interactions are stronger than pure component interactions. Molecules escape less easily, lowering vapour pressure below ideal. Example: chloroform and acetone, which form hydrogen bonds.

The key question to ask: do solute and solvent attract each other more or less than they attract their own kind?

The Colligative Properties Sequence

Students treat elevation of boiling point, depression of freezing point, osmotic pressure and lowering of vapour pressure as four separate topics.

They are all manifestations of the same underlying phenomenon: the presence of solute particles reduces the chemical potential of the solvent. Connecting them through this single concept makes all four easier to remember and apply.

ΔTb = Kb × m and ΔTf = Kf × m have the same structure. If you can derive one, you understand both. The subscripts change but the logic does not.

Mistake 3: Errors in Calculating Osmotic Pressure for Abnormal Solutes

Students apply π = CRT correctly for non-electrolytes but forget the van't Hoff factor (i) for electrolytes.

NaCl dissociates into two ions in solution, so i = 2. This means the observed colligative property is twice the calculated value for a non-electrolyte at the same concentration.

Students forget this factor, resulting in osmotic pressure values that are half what they should be. Always check whether the solute dissociates before calculating any colligative property.

Why Abnormal Molar Masses Confuse Students

When you calculate molar mass from colligative properties and get a value different from the actual molar mass, you have found an abnormal molar mass.

This happens because the actual number of particles in solution differs from the number of formula units dissolved. Electrolytes produce more particles (dissociation), giving a lower observed molar mass. Compounds that associate (like acetic acid in benzene, which forms dimers) produce fewer particles, giving a higher observed molar mass.

The van't Hoff factor explains both cases. If you understand the direction of the anomaly, you will never confuse dissociation with association.

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